Solubility (in molarity) of sparingly soluble | vedclass

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(D) Let the solubility of each salt be $S$ mol/$L$.For $MX$: $MX ightleftharpoons M^+ + X^-$,$K_{sp} = S 	imes S = S^2$.For $MX_2$: $MX_2 ightlef

Vedclass · Accepted Answer

$K_{sp}(MX) > K_{sp}(MX_2) > K_{sp}(MX_3)$

Vedclass · Answer

(D) Let the solubility of each salt be $S$ mol/$L$.For $MX$: $MX ightleftharpoons M^+ + X^-$,$K_{sp} = S 	imes S = S^2$.For $MX_2$: $MX_2 ightleftharpoons M^{2+} + 2X^-$,$K_{sp} = S 	imes (2S)^2 = 4S^3$.For $MX_3$: $MX_3 ightleftharpoons M^{3+} + 3X^-$,$K_{sp} = S 	imes (3S)^3 = 27S^4$.Since $S$ is the same for all,and assuming $S For a very small $S$,$S^2 > 4S^3 > 27S^4$ is generally not the case; rather,we compare the expressions. Given $S$ is the same,$K_{sp}(MX) = S^2$,$K_{sp}(MX_2) = 4S^3$,and $K_{sp}(MX_3) = 27S^4$. If $S$ is very small,$S^2$ is larger than $S^3$ and $S^4$. Thus,$K_{sp}(MX) > K_{sp}(MX_2) > K_{sp}(MX_3)$.

Solubility (in molarity) of sparingly soluble salts $MX, MX_2$ and $MX_3$ in water are same. The order of $K_{sp}$ of $MX, MX_2$ and $MX_3$ is

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